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The measured emf of the cell pt h2

SpletWhat will be the emf for the given cell pt H2 (g, P1) H+ (aq) H2 (g, P2) pt Shan chemistry Calculate the mass of urea (NH2CONH2) required in making 2.5 Kg of 0.25 … SpletApplication: The equilibrium constants of the reaction, difficult to measure can be calculated from the E0 value of the cell. Example 3.2: 2 Page Electrochemical cell and gibbs energy of reaction: Electrical work done per second =Electrical potential x Total charge To obtain maximum work from a galvanic cell, charge to be passed

Electrochemistry - ELECTROCHEMISTRY Redox Reactions An

SpletA voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 â C. The initial concentrations of Pb2+ and Cu2+ are 5.20Ã 10 â 2 M and 1.50 M, respectively. A) What is … SpletThe following cell has an EMF of +0.46 V. Cu Cu2+ Ag+ Ag ... (b) When the standard electrode potential for Fe3+(aq) / Fe2+(aq) is measured, a platinum electrode is required. (i) What is the function of the platinum electrode? ... (aq), Mn2+(aq) Pt Calculate the e.m.f. of this cell and write an equation for the spontaneous cell reaction. Cell e ... frederick gynecologist https://lcfyb.com

The emf of the cell, Pt H2 1 atm, H+ 0.1 M, 40 mL Ag+0.8 mM Ag …

SpletThe measured reversible EMF for the following cell Pt/H2 H+ Ag+ Ag at 25°C is found to be +0.58V. Compute the activity of Ag+. The standard electrode potential for the reduction … Splet38) The measured voltage of the cell Pt (s) H2 (1.0 atm) H (aq) Ag (1.0M) Ag (s) is 1.02 V at 25°C. Calculate the pH of the solution. A. 1.86 B. 1.69 C.3.72 D. 3.89 E. 7.43 07. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Splet07. avg. 2024 · Step 3: Add the two E 0 together to find the total cell EMF, E 0 cell E 0 cell = E 0 reduction + E 0 oxidation E 0 cell = 0.0000 V + 2.372 V = +2.372 V; Step 4: Determine … frederick half marathon 2021

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The measured emf of the cell pt h2

Electrochemistry and the Nernst Equation Problem 24-02-2024

SpletFor the cell shown, the measured cell potential, 𝐸cell , is −0.3577 V at 25 °C . Pt(s) H2(g,0.817 atm) H+(aq,? M) Cd2+(aq,1.00 M) Cd(s) The balanced reduction half … SpletCell Potential • Oxidizing agent pulls the electron. • Reducing agent pushes the electron. • The push or pull (“driving force”) is called the cell potential Ecell • Also called the electromotive force (emf) • Unit is the volt(V) • = 1 joule of work/coulomb of charge • Measured with a voltmeter

The measured emf of the cell pt h2

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SpletThe Nernst equation for the emf of the cell is E c e l l = E c e l l 0 − n F 2. 3 0 3 R T l o g {⌊ H + ⌋ 2 P H 2 } 2 × {P H 2 ⌊ H + ⌋ 2 } 1 . Since both the electrodes dip in same, solution, the … SpletThe e.m.f of the cell: Pt, H 2(1atm)∣HA(0.01M)∣∣HCl(1.0M)∣H 2(1atm), Pt is 0.295V. The dissociation constant of the acid HA is A 1.0×10 −4 B 1.0×10 −6 C 1.0×10 −8 D 1.0×10 −5 …

Splet07. avg. 2024 · The measured emf of the cell is – Pt (s) H2 (g, 1 bar) H+ (aq, 1M) Cu2+ (aq, 1M) Cu (s) is 0.34V. What is the standard electrode potential of the half-cell … SpletThe emf of the cell, Pt H2 1 atm, H+ 0.1 M, 40 mL Ag+0.8 mM Ag is 0.9 V. Calculate the emf when 60 mL of 0.05 M NaOH is added to the anodic compartment.Given: 2.303RTF = 0.06, log2 =0.3 ... = 0.44 V, the cell emf at 298 K is: Q. When 50 mL of 0.1 M NaOH is added to 50 mL of 0.1 M C H 3 C O O H solution, the pH will be: (use : ...

SpletQuestion: 3) The emf of the following cell was measured at 25°C and found to be 0.322 V. What is the pH of the solution ( recall pH = -log [H]) Pt/H2 (g) /HCI ( ? M, aq) / AgCl (s) / Ag Show transcribed image text Expert Answer Solution:- pH=1.68. (Not … View the full answer Transcribed image text: SpletWhat will be the reversible EMF at 25°C of the cell, Pt H2(g) (1 atm) H+ OH– O2(g) (1 atm) Pt, if at 26°C the emf increas by 0.001158 V. Q.48 Calculate the cell potential of a cell having reaction: Ag2S + 2e– l 2Ag + S2– in a solution buffered at pH = 3 and which is also saturated with 0.1 M H2S.

Splet05. apr. 2024 · Hint: First of all we will write Nernst equation. We will write the reaction of anode and cathode separately. Then we will add them both to get the complete cell equation. Then we will try to find the value of concentration from the cell equation and then we will find the value of ${K_a}$ by using the formula $[{H^ + }] = {H^ + } + {A^ - }$

Splet24. jan. 2024 · Standard EMF of a Cell The symbol E represents the emf generated by an electrochemical cell. With the help of a potentiometer, it may be measured. The value of emf is affected by the concentrations of reactants and products in the cell fluids, as well as the cell’s temperature. frederick gun show 2022SpletSolution for The emf of the following cell at 25° is 0.445V Pt, H2(1 atm)/H* (test solution) // KCI(sat.)/Hg.Cl2/Hg. Calculate the pH of the unknown solution. ... The emf of the cell Pt H2 (1 bar) ... ( 0.001 V)? b. To what precision must the potential be measured for the uncertainty in pH to be 0.02 pH unit? arrow_forward. For each reaction ... blickman ss shelvesSpletA voltage of 1.48 V is measured for this cell. Use this information to calculate the concentration of silver nitrate solution. (Given E°Zn2+/Zn= 0.76 V , E°Ag+/Ag= 0.8 0 v) 5. A copper-silver cell is set up. The copper ion concentration is 0.10 M. The concentration of silver ion is not known. The cell potential when measured was blickman nested instrument table- 7821ssSpletA: pH is used to measure acidity or basicity of an aqueous solution. pH of any solution can be… question_answer Q: Complete and balance the following equations for reac- tions taking place in basic solution. blickman keg washerSplet22. dec. 2024 · Correct option (d) pH of 0.1 M HCI and 0.1 M CH 3 COOH is not same.. Explanation : Since it is a concentration cell and the concentration of ions in two electrolyte solutions (HCl and CH 3 COOH) are different, therefore e.m.f. of this cell will not be zero. frederick habitat for humanity restoreSpletThe standard electromotive force of the cell Pt(s) H2(g) HCl(aq) AgCl(s) Ag(s) has been determined from 0°C to 90°C, and the data were found to fit the expression E/V = 0.237 – … blickman partsSpletConsider the cell, P t mid H2 (g, 1 atm) H+ (a q, 1 M) F e3+ (a q) F e2+ (a q) mid P t (s) Given that Eo F e3+ / F e2+=0.771 V, the ratio of concentration of F e (a q)2+ to F e (a q)3+ is, when the cell potential is 0.830 V. Q. Consider the cell, Pt ∣ H 2(g,1atm)H +(aq,1M)∥F e3+(aq) F e2+(aq) ∣ Pt(s) blickman products